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0.06x^2-1.6x+13=20
We move all terms to the left:
0.06x^2-1.6x+13-(20)=0
We add all the numbers together, and all the variables
0.06x^2-1.6x-7=0
a = 0.06; b = -1.6; c = -7;
Δ = b2-4ac
Δ = -1.62-4·0.06·(-7)
Δ = 4.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{4.24}}{2*0.06}=\frac{1.6-\sqrt{4.24}}{0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{4.24}}{2*0.06}=\frac{1.6+\sqrt{4.24}}{0.12} $
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